There are many things you can do with AJAX to improve the user experience, for example, Add, edit or delete the record and update the layout without reloading the page.
With only PHP you can easily delete records but require to submit the page or send value by URL and according to it delete a record.
This works and removes the record but it reloads the page every time.
You can do this with jQuery AJAX where you need to pass the record id from AJAX which needs to delete.
In the example, I am creating the HTML table which shows the list of records with a delete button. When the button gets clicked then remove the record and also remove the HTML table row with fadeOut() effect.
Contents
1. Table structure
I am using posts table in the example.
CREATE TABLE `posts` ( `id` int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT, `title` varchar(100) NOT NULL, `content` text NOT NULL, `link` varchar(255) NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1;
2. Configuration
Create a config.php file for the database connection.
Completed Code
<?php
$host = "localhost"; /* Host name */
$user = "root"; /* User */
$password = ""; /* Password */
$dbname = "tutorial"; /* Database name */
$con = mysqli_connect($host, $user, $password,$dbname);
// Check connection
if (!$con) {
die("Connection failed: " . mysqli_connect_error());
}
3. HTML
List records from posts table in the <table >.
Here, I add the <span class='delete'> for deleting the record and store delete id in data-id variable.
Completed Code
<div class='container'>
<table border='1' >
<tr style='background: whitesmoke;'>
<th>S.no</th>
<th>Title</th>
<th>Operation</th>
</tr>
<?php
$query = "SELECT * FROM posts";
$result = mysqli_query($con,$query);
$count = 1;
while($row = mysqli_fetch_array($result) ){
$id = $row['id'];
$title = $row['title'];
$link = $row['link'];
?>
<tr>
<td align='center'><?= $count; ?></td>
<td><a href='<?= $link; ?>'><?= $title; ?></a></td>
<td align='center'>
<span class='delete' data-id='<?= $id; ?>'>Delete</span>
</td>
</tr>
<?php
$count++;
}
?>
</table>
</div>
4. PHP
Create a remove.php file.
Read POST id.
Check if a record exists or not in the posts table. If exists then execute the Delete query on the id and return 1 otherwise return 0.
Completed Code
<?php
include "config.php";
$id = 0;
if(isset($_POST['id'])){
$id = mysqli_real_escape_string($con,$_POST['id']);
}
if($id > 0){
// Check record exists
$checkRecord = mysqli_query($con,"SELECT * FROM posts WHERE id=".$id);
$totalrows = mysqli_num_rows($checkRecord);
if($totalrows > 0){
// Delete record
$query = "DELETE FROM posts WHERE id=".$id;
mysqli_query($con,$query);
echo 1;
exit;
}else{
echo 0;
exit;
}
}
echo 0;
exit;
5. jQuery
Define click event on delete class.
Read delete id from data-id attribute and assign it in deleteid variable.
Send AJAX post request to 'remove.php' file. Pass deleteid as data.
On AJAX successfully callback check response.
If response == 1 then remove a row using remove() and use fadeOut() effect to add some delay.
If response != 1 then alert('Invalid ID.');.
Completed Code
$(document).ready(function(){
// Delete
$('.delete').click(function(){
var el = this;
// Delete id
var deleteid = $(this).data('id');
var confirmalert = confirm("Are you sure?");
if (confirmalert == true) {
// AJAX Request
$.ajax({
url: 'remove.php',
type: 'POST',
data: { id:deleteid },
success: function(response){
if(response == 1){
// Remove row from HTML Table
$(el).closest('tr').css('background','tomato');
$(el).closest('tr').fadeOut(800,function(){
$(this).remove();
});
}else{
alert('Invalid ID.');
}
}
});
}
});
});
6. Demo
7. Conclusion
In this post, I explained how you can use AJAX to delete existing records from MySQL Table. I used it with HTML table in the demonstration you can also use it with <div>, <ul>, etc. elements.
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